document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1098063>Question 1098063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number 100 is separated into two parts such that if 1/3 of one part is subtracted from 1/4 of the other, the difference is 11. Find the two parts.\r<BR>\n" );
document.write( "\n" );
document.write( "Write your answers in ascending order. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712461 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100 = x + y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1/4 * x - 1/3 * y = 11\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiply both sides by 12 to get:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "3 * x - 4 * y = 132\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "solve for x to get x = (4y + 132) / 3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "replace x with it's equivalent value and your original equation of 100 = x + y becomes:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "100 = (4y + 132) / 3 + y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiply both sides of this equation by 3 to get:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "300 = 4y + 132 + 3y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "combine like terms to get 300 = 7y + 132\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "solve for y to get y = (300 - 132) / 7\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "this results in y = 24\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "since 100 = x + y, then x must be equal to 76 when y = 24.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1/4 * x - 1/3 * y = 11 becomes 1/4 * 76 - 1/3 * 24 = 11 which becomes 19 - 8 = 11 which becomes 11 = 11 which is true.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the two parts are 24 and 76 in ascending order.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );