document.write( "Question 1097884: x + y = 31
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document.write( "(2/3)x = (5/8)y\r
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document.write( "16x = 15y\r
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document.write( "x + y = 31 -------(1)
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document.write( "16x – 15y = 0------(2)\r
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document.write( "Multiply equation (1) by 16\r
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document.write( "16x + 16y = (31)(16)
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document.write( "16x – 15y = 0\r
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document.write( "Subtract the two equation \r
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document.write( "31y = 31(16)\r
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document.write( "Y = 16\r
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document.write( "Input y = 16 in equation (1)\r
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document.write( "x + y = 31\r
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document.write( "x= 31 – y = 31 – 16 = 15\r
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document.write( "Thus x = 15 and y = 16\r
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document.write( "Therefore the two values are 15 and 16 \n" );
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Algebra.Com's Answer #712451 by Sc_moore(1)![]() ![]() You can put this solution on YOUR website! x + y = 31 \n" ); document.write( "(2/3)x = (5/8)y\r \n" ); document.write( "\n" ); document.write( "16x = 15y\r \n" ); document.write( "\n" ); document.write( "x + y = 31 -------(1) \n" ); document.write( "16x – 15y = 0------(2)\r \n" ); document.write( "\n" ); document.write( "Multiply equation (1) by 16\r \n" ); document.write( "\n" ); document.write( "16x + 16y = (31)(16) \n" ); document.write( "16x – 15y = 0\r \n" ); document.write( "\n" ); document.write( "Subtract the two equation \r \n" ); document.write( "\n" ); document.write( "31y = 31(16)\r \n" ); document.write( "\n" ); document.write( "Y = 16\r \n" ); document.write( "\n" ); document.write( "Input y = 16 in equation (1)\r \n" ); document.write( "\n" ); document.write( "x + y = 31\r \n" ); document.write( "\n" ); document.write( "x= 31 – y = 31 – 16 = 15\r \n" ); document.write( "\n" ); document.write( "Thus x = 15 and y = 16\r \n" ); document.write( "\n" ); document.write( "Therefore the two values are 15 and 16 \n" ); document.write( " |