document.write( "Question 1097962: Please help me solve this word problem:
\n" ); document.write( "You are saving $590 a week to buy a new computer. Your brother is saving at a weekly rate of 4^{x-2}, if x = the number of weeks of saving. What is the first week that your brother will have more money saved than you? \r
\n" ); document.write( "\n" ); document.write( "When I solved it I got 7 but then realized that each week is increasing by 590 for the person. I don't know what to do.
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Algebra.Com's Answer #712418 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The \"You\" person is saving \"%22%24590%22\" per week,
\n" ); document.write( "so after \"n\" weeks, the saving for that person (in $) would be
\n" ); document.write( "\"590n\" .
\n" ); document.write( "The savings grow linearly.
\n" ); document.write( "
\n" ); document.write( "The amounts the brother would save (in $) would be
\n" ); document.write( "\"4%5E%281-2%29=4%5E%28-1%29=0.25\" for week 1,
\n" ); document.write( "\"4%5E%282-2%29=4%5E0=1\" for week 2,
\n" ); document.write( "\"4%5E%283-2%29=4%5E1=4\" for week 3,
\n" ); document.write( "\"4%5E%284-2%29=4%5E2=16\" for week 4,
\n" ); document.write( "and so on.
\n" ); document.write( "The weekly savings form a geometric sequence
\n" ); document.write( "(or geometric progression, or GP, as you wish to call it).
\n" ); document.write( "The dirst term \"b=0.25\" ,
\n" ); document.write( "the common ratio is \"r=4\" ,
\n" ); document.write( "and the sum of the first \"n\" terms is
\n" ); document.write( " .
\n" ); document.write( "The brother's savings grow exponentially.
\n" ); document.write( "
\n" ); document.write( "At the beginning the \"you\" person will have more saved,
\n" ); document.write( "but the brother is a faster saver,
\n" ); document.write( "and would soon have more saved than the you person.
\n" ); document.write( "
\n" ); document.write( "That would happen when
\n" ); document.write( "\"4%5E%28n-1%29%2F3-0.25%2F3%3E590n\" .
\n" ); document.write( "It is easy to get to the answer by calculating both sides for a few values of \"n\" .
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\n" ); document.write( "CALCULATING FOR A FEW \"n\" VALUES:
\n" ); document.write( "For \"n=6\" , \"590n=590%2A6=3540\" and \"%284%5E%28n-1%29-0.25%29%2F3=%284%5E5-0.25%29%2F3=%281024-0.25%29%2F3=1023.75%2F3=341.25\" ,
\n" ); document.write( "so the brother does not have the most savings.
\n" ); document.write( "For \"n=8\" , \"590n=590%2A8=4720\" and \"%284%5E%28n-1%29-0.25%29%2F3=%284%5E7-0.25%29%2F3=%2896384-0.25%29%2F3=96383.75%2F3=5461.25\" ,
\n" ); document.write( "and the brother have more savings than the \"you\" person.
\n" ); document.write( "What about for \"n=7\" ?
\n" ); document.write( "For \"n=7\" , \"590n=590%2A7=5310\" and \"%284%5E%28n-1%29-0.25%29%2F3=%284%5E6-0.25%29%2F3=%284096-0.25%29%2F3=4095.75%2F3=1365.25\" , and the \"you\" person still has nore savings than the brother.
\n" ); document.write( "So the first time that the brother has more money saved than the you person is
\n" ); document.write( "when the brother has \"highlight%288%29\" weeks worth of savings.
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