document.write( "Question 1098001: A catering service offers 11 appetizers, 4 main courses, and 9 desserts. A banquet chairperson is to select 5 appetizers, 3 main courses, and 3 desserts for a banquet. In how many ways can this be done? \n" ); document.write( "
Algebra.Com's Answer #712401 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
There are \"11%2A10%2A9%2A8%2A7\" ordered lists of \"5\" appetizers that can be written, but each set of \"5\" appetizers would be repeated in different order in \"5%2A4%2A3%2A2\" lists.
\n" ); document.write( "So, there are \"11%2A10%2A9%2A8%2A7%2F%282%2A3%2A4%2A5%29\" different sets of \"5\" appetizers that can be selected, from the \"11\" appetizers available.
\n" ); document.write( "
\n" ); document.write( "There are \"4%29\" different sets of \"3\" main courses that can be selected from the \"4\" main courses available. (It is just a question of deciding which of the 4 main courses to exclude).
\n" ); document.write( "
\n" ); document.write( "There are \"9%2A8%2A7%2F%282%2A3%29\" different sets of \"3\" desserts that can be selected from the \"9\" desserts available.
\n" ); document.write( "
\n" ); document.write( "Combining the possible choices for appetizer, main course, and dessets selections, the number of posssible banquet menus is
\n" ); document.write( " .
\n" ); document.write( "Simplifying, you get
\n" ); document.write( "
\n" ); document.write( "
\n" );