document.write( "Question 14230: two thirds X plus four equals nine
\n" ); document.write( "2/3 x + 4 = 9 how do you solve and do the work? \n" ); document.write( "
Algebra.Com's Answer #7124 by Alwayscheerful(414)\"\" \"About 
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You first need to isolate the X on one side in order to solve this problem.
\n" ); document.write( "So, move everything so that the 2/3X is by itself on the left side of the equal sign.
\n" ); document.write( "*Remember that everytime you move something over the equal sign, you must change its sign. For example. x+5=10. If you move the 5 over, you change it from a positive state to a negative state. Then the equation becomes x=5\r
\n" ); document.write( "\n" ); document.write( "Back you your problem...
\n" ); document.write( "2/3x+4=9
\n" ); document.write( "Move the 4 over
\n" ); document.write( "2/3x=5
\n" ); document.write( "Then, to get rid of the fraction, you multipy the fraction by its recipricol (flip the fraction upside-down) to the make coefficient 1\r
\n" ); document.write( "\n" ); document.write( "3/2*2/3 x=5
\n" ); document.write( "*Remember that if you multiply one side with something, you must do the same for the other side.
\n" ); document.write( "x=5*3/2
\n" ); document.write( "x=7.5
\n" ); document.write( " or
\n" ); document.write( "x=15/2 \n" ); document.write( "
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