document.write( "Question 97910This question is from textbook Prentice Hall Pre- Algebra
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document.write( "A woman jogging at 6mi/h passes a man biking in the opposite direction at 12mi/h. If they maintain their speeds, how far from each other will they be in 10 min after passing?\r
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Algebra.Com's Answer #71230 by mathslover(157)![]() ![]() You can put this solution on YOUR website! Distance covered by the woman in 10 minutes =speed* time \n" ); document.write( " =6 * 10/60 (since 10 minutes = 10/60 hr) \n" ); document.write( " = 1 mile\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance covered by the man in 10 minutes = 12* 10/60 \n" ); document.write( " = 2mile\r \n" ); document.write( "\n" ); document.write( "therefore they are (1+2) = 3miles apart after 10 minutes \n" ); document.write( " |