document.write( "Question 97910This question is from textbook Prentice Hall Pre- Algebra
\n" ); document.write( ": Please help me with this question!!! I would also like o thank you in advance for all your time and efforts put into solving this problem!!\r
\n" ); document.write( "\n" ); document.write( "A woman jogging at 6mi/h passes a man biking in the opposite direction at 12mi/h. If they maintain their speeds, how far from each other will they be in 10 min after passing?\r
\n" ); document.write( "\n" ); document.write( "Thank you, Thank you, THANK YOU!!
\n" ); document.write( "

Algebra.Com's Answer #71228 by aaaaaaaa(138)\"\" \"About 
You can put this solution on YOUR website!
Uhm...\r
\n" ); document.write( "\n" ); document.write( "Woman -> \"6mi%2Fh\" = \"cross%286%29mi%2Fcross%2860%29min\" = \"1mi%2F10min\"
\n" ); document.write( "Bikeman -> \"12mi%2Fh\" = \"cross%2812%29mi%2Fcross%2860%29min\" = \"1mi%2F5min\" = \"2mi%2F10min\"\r
\n" ); document.write( "\n" ); document.write( "In 10 minutes the woman will have walked 1 mile, while the bikerman will have walked 2 miles. As they're walking in opposite directions, they'll be three miles apart.
\n" ); document.write( "
\n" );