document.write( "Question 1097847: This is my problem: A two-digit counting number has a value that is 8 times the sum of its digits. If 6 times the units' digit is 5 more than the tens' digit, what is the number? My math book has not given me an example of this variation of kind of problem, and I can't find one on YouTube. Can you help me learn to solve this? Walk me through the different steps? Thank you for your time! \n" ); document.write( "

Algebra.Com's Answer #712271 by ikleyn(52775) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Let T be the tens digit and U be the ones digit.\r\n" );
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document.write( "Then your number N is N = 10*T + U.\r\n" );
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document.write( "First part of the condition gives you this equation:\r\n" );
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document.write( "10*T + U = 8*(T+U).    (1)\r\n" );
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document.write( "Second part of the condition gives you another equation:\r\n" );
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document.write( "6*U = T + 5.           (2)\r\n" );
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document.write( "Thus you have this system of two equations\r\n" );
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document.write( "10*T + U = 8*(T+U),    (1)\r\n" );
document.write( " 6*U = T + 5.          (2)\r\n" );
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document.write( "which you can easily solve.\r\n" );
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document.write( "Since I do not want to deprive you this pleasure to solve it on your own, I leave the solution to you.\r\n" );
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