document.write( "Question 1097642: x/6+y/2+z/6=1/2
\n" ); document.write( "x+y+z=5
\n" ); document.write( "x/3+y/2+z/6=1 \n" ); document.write( "
Algebra.Com's Answer #712212 by Boreal(15235)\"\" \"About 
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x/6+y/2+z/6=1/2
\n" ); document.write( "x+y+z=5
\n" ); document.write( "x/3+y/2+z/6=1
\n" ); document.write( "================
\n" ); document.write( "x+3y+z=3
\n" ); document.write( "x+y+z=5
\n" ); document.write( "2x+3y+z=6
\n" ); document.write( "===============
\n" ); document.write( "-x-3y-z=-3
\n" ); document.write( "2x+3y+z=6
\n" ); document.write( "x=3
\n" ); document.write( "================
\n" ); document.write( "6+3y+z=6; 3y+z=0,z=-3y
\n" ); document.write( "3+y-3y=5
\n" ); document.write( "3-2y=5
\n" ); document.write( "y=-1
\n" ); document.write( "(3, -1, 3)
\n" ); document.write( "Check
\n" ); document.write( "(1/2)-(1/2)+3/6=1/2 TRUE
\n" ); document.write( "3-1+3=5, TRUE
\n" ); document.write( "1+(-1/2)+(1/2)=1 TRUE\r
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