document.write( "Question 1097610: In a factory it is known from past experience that the probability is 0.75 that a new worker
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document.write( "who has attended the company training program will meet the production quota, and the
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document.write( "corresponding probability for a new worker who has not attended the company training
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document.write( "program is 0.50. If 60% of the new workers attend the training program,
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document.write( "3.1 What is the probability that a new worker will meet the production quota? [3]
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document.write( "3.2 What is the probability that a new worker, who meets the production quota, attended
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document.write( "the company’s training program? [3] \n" );
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Algebra.Com's Answer #712210 by Boreal(15235) You can put this solution on YOUR website! =======Attend=====Not===totals \n" ); document.write( "Meets----45--------20----65 \n" ); document.write( "doesn't--15--------20----35 \n" ); document.write( "totals---60--------40---100\r \n" ); document.write( "\n" ); document.write( "I used 100 workers, of whom 60 attended and of those 75% met production quota and 25% did not. That is the first column. The 2nd column does it with 50%, and the sums add to 100 \n" ); document.write( "For 1, the probability of meeting is 0.65 \n" ); document.write( "For 2, the worker who meets (65) attended (45) is 45/65=9/13=0.69 \n" ); document.write( " |