document.write( "Question 1097763: The length of rectangle is 2 inches less than twice its width.if the area of the rectangle is 112 square inches.find the length of the shorter leg. \n" ); document.write( "
Algebra.Com's Answer #712187 by Jeetbhatt10th(11)\"\" \"About 
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Let width be x units
\n" ); document.write( "therefore length=2x-2
\n" ); document.write( "Since area = length×breadth
\n" ); document.write( "Therefore 112=(2x-2)(x)
\n" ); document.write( "2x^2-2x=112
\n" ); document.write( "x^2-x=56
\n" ); document.write( "x^2-x-56=0
\n" ); document.write( "x^2-8x+7x-56=0
\n" ); document.write( "x (x-8)+7 (x-8)=0
\n" ); document.write( "(x+7)(x-8)=0
\n" ); document.write( "=>x=8,-7
\n" ); document.write( "But length cannot be negative,thus x=8
\n" ); document.write( "Width=8 inches
\n" ); document.write( "Length=2x-2=2×8-2=14 inches
\n" ); document.write( "Hence dimensions are 14 inches and 8 inches (Answer)☺\r
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