document.write( "Question 97903: kaylene is 30 yrs. old and jessica is 22 yrs. old. how many years ago was kaylene twice as old as jessica? \n" ); document.write( "
Algebra.Com's Answer #71218 by rajagopalan(174)![]() ![]() You can put this solution on YOUR website! Let the number of years =x \n" ); document.write( "then x years ago.... \n" ); document.write( "kaylene was 30 - x \n" ); document.write( "jessica was 22-x \n" ); document.write( "But according to condition, 2*(22-x)=30-x \n" ); document.write( "44-2x=30-x \n" ); document.write( "44-30=-x+2x \n" ); document.write( "14=x\r \n" ); document.write( "\n" ); document.write( "So the answer is 14 years \n" ); document.write( "Verify: \n" ); document.write( "14 years ago.... kaylene was 30 - x =30-14=16 \n" ); document.write( "14 years ago.... jessica was 22-x =22-14=8 \n" ); document.write( "then 16/8 = 2 ok\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |