document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097734>Question 1097734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cards are drawn without replacement from a standard deck of <BR>\n" );
document.write( "52 playing cards.  What is the probability of choosing a spade and then, without replacement, a club?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712171 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability of getting a spade out of a full deck is 13/52.\r<BR>\n" );
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document.write( "probability of getting a club is 13/51 after a spade has been drawn from the deck because there is one less card in the deck.\r<BR>\n" );
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document.write( "the probability of getting a spade and then a club is therefore 13/52 * 13/51.\r<BR>\n" );
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