document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97911>Question 97911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One morning, John drove 5 hours before stopping to eat. After lunch he increased his speed by 10 mph. If he completed a 430 mile trip in 8 hrs of driving time, how fast did he drive in the morning? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71217 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the morning speed =x<BR>\n" );
document.write( "Driving time 5 hrs<BR>\n" );
document.write( "Distance covered = speedxtime =5x........D1<BR>\n" );
document.write( "Post lunch travel time =8-5=3<BR>\n" );
document.write( "Post lunch speed=x+10<BR>\n" );
document.write( "Post Lunch Distance covered = speedxtime =3(x+10)=3x+30......D2<BR>\n" );
document.write( "Total distance covered=D1+D2=5x+3x+30<BR>\n" );
document.write( "But 5x+3x+30 = 430<BR>\n" );
document.write( "8x+30=430<BR>\n" );
document.write( "8x=430-30<BR>\n" );
document.write( "8x=400<BR>\n" );
document.write( "x=400/8=50<BR>\n" );
document.write( "The speed in the morning = 50 mph<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );