document.write( "Question 1097748: I am 12 years old and my brother is 5 years old. In how many years will I be twice as old as my brother? \n" ); document.write( "
Algebra.Com's Answer #712168 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
let x be the number of years from now.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your equation becomes 20 + x = 2 * (5 + x)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "simplify this equation to get 20 + x = 10 + 2x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "subtract 10 from both sides of this equation and subtract x from both sides of this equation to get 10 = x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that's your solution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "in 10 years, you will be twice as old as your brother.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "20 + 30 = 30
\n" ); document.write( "5 + 10 = 15\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "30 is two times 15.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );