document.write( "Question 1097690: Solve the following system of equations by any method.\r
\n" ); document.write( "\n" ); document.write( "x/6 +y/2+ z/6 =1/2
\n" ); document.write( "x+y+z=5
\n" ); document.write( "x/3 +y/2 +z/6= 1 \n" ); document.write( "
Algebra.Com's Answer #712156 by Jeetbhatt10th(11)\"\" \"About 
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x/6+y/2+z/6=1/2
\n" ); document.write( "Taking lcm,
\n" ); document.write( "(x+3y+z)/6=1/2
\n" ); document.write( "x+3y+z=3.. (1)
\n" ); document.write( "x+y+z=5.. (2)
\n" ); document.write( "Subtracting (2) from (1) ,we get
\n" ); document.write( "X+3y+z-x-y-z=3-5
\n" ); document.write( "2y=-2
\n" ); document.write( "Y=-1.. (3)
\n" ); document.write( "Substituting (3) in (1),we get,
\n" ); document.write( "x+3 (-1)+z=3
\n" ); document.write( "x-3+z=3
\n" ); document.write( "x+z=6.. (4)
\n" ); document.write( "Since x/3+y/2+z/6=1
\n" ); document.write( "=> (2x+3y+z)/6=1
\n" ); document.write( "2x+3y+z=6.. (5)
\n" ); document.write( "Substituting (3)in (5),we get
\n" ); document.write( "2x-3+z=6
\n" ); document.write( "2x+z=9.. (6)
\n" ); document.write( "Subtracting (4)from (6) we get
\n" ); document.write( "2x-x+z-z=9-6
\n" ); document.write( "x=3.. (7)
\n" ); document.write( "Substituting (7) in (4)
\n" ); document.write( "3+z=6
\n" ); document.write( "z=3
\n" ); document.write( "Hence,x=3,y=-1,z=3 (Answer)😊 \n" ); document.write( "
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