document.write( "Question 1097683: In a purse Misty has 1.91, including one more nickel than quarters. She also has twice as many dimes as nickels. But, she also has eight more pennies than dimes. How many of each of the four coins does Misty have?\r
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\n" ); document.write( "So what I did was use the formula: Quantity X Value = Subtotal.
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Algebra.Com's Answer #712155 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Not necessarily the neatest way, but...
\n" ); document.write( "p pennies
\n" ); document.write( "n nickels
\n" ); document.write( "d dimes
\n" ); document.write( "q quarters\r
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\n" ); document.write( "\n" ); document.write( "\"system%281p%2B5n%2B10d%2B25q=191%2Cn-q=1%2Cd%2Fn=2%2Cp-d=8%29\"------four equations in four variables\r
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\n" ); document.write( "\n" ); document.write( "\"system%28p%2B5n%2B10d%2B25q=191%2Cn-q=1%2Cd=2n%2Cp-d=8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=p-8\"
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\n" ); document.write( "\"system%28p-8=2n%2Cn-q=1%2Cp%2B5n%2B10%28p-8%29%2B25q=191%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%2B5n%2B10p-80%2B25q=191\"
\n" ); document.write( "\"11p%2B5n%2B25q=191%2B80\"\r
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\n" ); document.write( "\n" ); document.write( "REVISE in three variables:
\n" ); document.write( "\"system%2811p%2B5n%2B25q=271%2Cp=2n%2B8%2Cq=n-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute for p and q.
\n" ); document.write( "\"11%282n%2B8%29%2B5n%2B25%28n-1%29=271\"\r
\n" ); document.write( "\n" ); document.write( "\"22n%2B88%2B5n%2B25n-25=271\"\r
\n" ); document.write( "\n" ); document.write( "\"52n=271-88%2B25\"\r
\n" ); document.write( "\n" ); document.write( "\"52n=208\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28n=4%29\" how many nickels-----------you can find the other coins from this.
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