document.write( "Question 1097710: A rectangular field with an area of 8000m^ is enclosed by 400m of fencing. Determine the dimensions of the field to the nearest tenth of a metre. \n" ); document.write( "
Algebra.Com's Answer #712120 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+W+\" = the width of the field
\n" ); document.write( "Let \"+L+\" = the length of the field
\n" ); document.write( "\"+2L+%2B+2W+=+400+\"
\n" ); document.write( "\"+2L+=+400+-+2W+\"
\n" ); document.write( "\"+L+=+200+-+W+\"
\n" ); document.write( "-------------------------
\n" ); document.write( "Now I can say:
\n" ); document.write( "\"+W%2A%28+200+-+W+%29+=+8000+\"
\n" ); document.write( "\"+-W%5E2+%2B+200W+-+8000+=+0+\"
\n" ); document.write( "Use qudratic formula
\n" ); document.write( "\"+W+=+%28+-b+%2B-sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29%2F%282a%29+\"
\n" ); document.write( "\"+a+=+-1+\"
\n" ); document.write( "\"+b+=+200+\"
\n" ); document.write( "\"+c+=+-8000+\"
\n" ); document.write( "\"+W+=+%28+-200+%2B-sqrt%28+40000+-+4%2A%28-1%29%2A%28-8000%29+%29%29%2F%282%2A%28-1%29%29+\"
\n" ); document.write( "\"+W+=+%28+-200+%2B-sqrt%28+40000+-+32000+%29%29%2F%28-2%29+\"
\n" ); document.write( "\"+W+=+%28+-200+%2B-sqrt%28+8000+%29+%29+%2F%28-2%29+\"
\n" ); document.write( "\"+W+=+%28+-200+%2B+89.443+%29+%2F+%28-2%29+\"
\n" ); document.write( "This solution doesn't work since you end up with negative answer, so
\n" ); document.write( "\"+W+=+%28+-200+-+89.443+%29+%2F+%28-2%29+\"
\n" ); document.write( "\"+W+=+%28+-289.443+%29+%2F+%28-2%29+\"
\n" ); document.write( "\"+W+=+144.7+\"
\n" ); document.write( "\"+L+=+200+-+W+\"
\n" ); document.write( "\"+L+=+200+-+144.7+\"
\n" ); document.write( "\"+L+=+55.3+\"
\n" ); document.write( "The field is 55.3 by 144.7
\n" ); document.write( "----------------------------
\n" ); document.write( "Check answer:
\n" ); document.write( "\"+L%2AW+=+8000+\"
\n" ); document.write( "\"+55.3%2A144.7+=+8000+\"
\n" ); document.write( "\"+8001.91+=+8000+\"
\n" ); document.write( "Error due to rounding off, think
\n" ); document.write( "also:
\n" ); document.write( "\"+2W+%2B+2L+=+400+\"
\n" ); document.write( "\"+2%2A144.7+%2B+2%2A55.3+=+400+\"
\n" ); document.write( "\"+289.4+%2B+110.6+=+400+\"
\n" ); document.write( "\"+400+=+400+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );