document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097676>Question 1097676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 21.3/4 of one of the numbers added to 2/3 of the other gives a sum of 15. Find the two numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712100 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712100\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=21<BR>\n" );
document.write( "3/4x+2/3y=15<BR>\n" );
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document.write( "y=21-x<BR>\n" );
document.write( "3/4x+2/3(21-x)=15<BR>\n" );
document.write( "3/4x+14-2/3x=15<BR>\n" );
document.write( "9/12x-8/12x=15-14<BR>\n" );
document.write( "1/12x=1<BR>\n" );
document.write( "x=(1/1)/(1/12)<BR>\n" );
document.write( "x=1/1*12/1<BR>\n" );
document.write( "x=12<BR>\n" );
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document.write( "3/4*12+2/3y=15<BR>\n" );
document.write( "9+2/3y=15<BR>\n" );
document.write( "2/3y=15-9<BR>\n" );
document.write( "y=6/(2/3)<BR>\n" );
document.write( "y=6*3/2<BR>\n" );
document.write( "y=9<BR>\n" );
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document.write( "x+y=21<BR>\n" );
document.write( "12+9=21<BR>\n" );
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