document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097649>Question 1097649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the  equation of the line with a slope of 2.3 and travels through the point (4, 6).\r<BR>\n" );
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document.write( "* So first I tried to figure out  what is m? what is b? Then try to plug them into the formula: y=mx+b. As a result, I found out that m= 2/3, x=4 and y=-6. The only thing we don't know is what is b.\r<BR>\n" );
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document.write( "*-6= 2/3(4)+ b<BR>\n" );
document.write( "-6= 2.6666+ b (here is where I got confused because of what I got)<BR>\n" );
document.write( "-2.6666=-2.6666 (subtract both sides of the equation by the 2.6666)<BR>\n" );
document.write( "b=-8.6666\r<BR>\n" );
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document.write( "So then I go to plug in the b to the y=mx+b<BR>\n" );
document.write( "-6= 2/3(4)+ (-8.6666)<BR>\n" );
document.write( "*It's all supposed to equal -6, but what I get instead is -5.999933333. \r<BR>\n" );
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document.write( "Am I doing something wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #712074 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20060)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=712074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line with a slope of 2.3 and travels through the point (4, 6). <BR>\n" );
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document.write( "Plug in m=2.3 x=4, y=6 in\r\n" );
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document.write( "   y = mx+b\r\n" );
document.write( "   6 = 2.3(4) + b\r\n" );
document.write( "   6 = 9.2 + b\r\n" );
document.write( "-3.2 = b\r\n" );
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document.write( "Substitute m=2.3, b=-3.2, x=x, y=y in\r\n" );
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document.write( "   y = mx+b\r\n" );
document.write( "   y = 2.3x+(-3.2)\r\n" );
document.write( "   y = 2.3x-3.2\r\n" );
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document.write( "* So first I tried to figure out what is m? <BR>\n" );
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document.write( "You are given m, the slope, as 2.3\r\n" );
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document.write( "what is b? <BR>\n" );
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document.write( "You find that as I did above, as b=-3.2\r\n" );
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document.write( "Then try to plug them into the formula: y=mx+b. As a result, I found out that m= 2/3, x=4 and y=-6.<BR>\n" );
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document.write( "Oh, I see.  You made a typo and typed 2.3 when you meant to type 2/3.\r\n" );
document.write( "OK.\r\n" );
document.write( "Plug in m=2/3 x=4, y=6 in\r\n" );
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document.write( "   y = mx+b\r\n" );
document.write( "   6 = (2/3)(4) + b\r\n" );
document.write( "   6 = 8/3 + b\r\n" );
document.write( "Multiply through by 3 to clear the fraction\r\n" );
document.write( "  18 = 8 + 3b\r\n" );
document.write( "  10 = 3b\r\n" );
document.write( "10/3 = b  \r\n" );
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document.write( "Substitute m=2/3, b=10/3, x=x, y=y in\r\n" );
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document.write( "   y = mx+b\r\n" );
document.write( "   y = (2/3)x+(10/3)\r\n" );
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document.write( " The only thing we don't know is what is b. <BR>\n" );
document.write( "*-6= 2/3(4)+ b<BR>\n" );
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document.write( "Why did you substitute -6 for y? You should have substituted 6\r\n" );
document.write( "because you said above that it travels through (4, 6), not \r\n" );
document.write( "(4, -6).  Did you make another typo on the point?\r\n" );
document.write( "OK. I'll assume you meant m=2/3 and travels through (4, -6), not (4,6).\r\n" );
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document.write( "Plug in m=2/3 x=4, y=-6 in\r\n" );
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document.write( "    y = mx+b\r\n" );
document.write( "   -6 = (2/3)(4) + b\r\n" );
document.write( "   -6 = 8/3 + b\r\n" );
document.write( "Multiply through by 3 to clear the fraction\r\n" );
document.write( "  -18 = 8 + 3b\r\n" );
document.write( "  -26 = 3b\r\n" );
document.write( "-26/3 = b  \r\n" );
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document.write( "Substitute m=2/3, b=-26/3, x=x, y=y in\r\n" );
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document.write( "   y = mx+b\r\n" );
document.write( "   y = (2/3)x+(-26/3)\r\n" );
document.write( "   y = (2/3)x-26/3\r\n" );
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document.write( "-6= 2.6666+ b (here is where I got confused because of what I got)<BR>\n" );
document.write( "-2.6666=-2.6666 (subtract both sides of the equation by the 2.6666)<BR>\n" );
document.write( "b=-8.6666<BR>\n" );
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document.write( "That's approximately correct.  However you should be using\r\n" );
document.write( "fractions, not rounded off decimals.  -26/3 is only approximately\r\n" );
document.write( "equal to -8.6666, and BTW if you were going to round off, it would\r\n" );
document.write( "have been -8.6667, not -8.6666.  But you should have used the \r\n" );
document.write( "fraction -26/3.\r\n" );
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document.write( "So then I go to plug in the b to the y=mx+b\r\n" );
document.write( "-6= 2/3(4)+ (-8.6666)\r\n" );
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document.write( "No. After you have found the slope, you don't substitute the point\r\n" );
document.write( "again as you did to find b.  The second time you substitute you leave \r\n" );
document.write( "x as just the letter x, and y as just the letter y.  You don't \r\n" );
document.write( "substitute anything for them to get the final equation.\r\n" );
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document.write( "So the equation should be\r\n" );
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document.write( "y = (2/3)x + (-26/3)\r\n" );
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document.write( "*It's all supposed to equal -6, but what I get instead is -5.999933333. <BR>\n" );
document.write( "Am I doing something wrong?<BR>\n" );
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document.write( "Yes, you are using a rounded off decimal instead of the fraction. On\r\n" );
document.write( "top of that, you rounded off incorrectly, and made two typos, once\r\n" );
document.write( "in typing 2.3 for 2/3 and again typing (4,6) for (4,-6).\r\n" );
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document.write( "Edwin</PRE> </SPAN>\n" );
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