document.write( "Question 1097235: Twice a number is no less than 10 units from -1 \n" ); document.write( "

Algebra.Com's Answer #712017 by math_helper(2461) $\"\"$ $\"About$

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\n" ); document.write( "A number: x
\n" ); document.write( "Twice a number: 2x
\n" ); document.write( "No less than 10 units from -1: | 2x - (-1) | >= 10
\n" ); document.write( "
\n" ); document.write( "| 2x + 1 | >= 10\r
\n" ); document.write( "\n" ); document.write( "Two cases to consider, the first is 2x + 1 <= -10\r
\n" ); document.write( "\n" ); document.write( "2x + 1 <= -10
\n" ); document.write( " 2x <= -11
\n" ); document.write( " x <= -11/2\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( " 2nd case: 2x + 1 >= 10
\n" ); document.write( " 2x + 1 >= 10
\n" ); document.write( " 2x >= 9
\n" ); document.write( " x >= 9/2\r
\n" ); document.write( "\n" ); document.write( "—\r
\n" ); document.write( "\n" ); document.write( "The solution regions are $\"+highlight%28x+%3C=+-11%2F2%29+\"$ and $\"+highlight%28x+%3E=+9%2F2%29+\"$
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