document.write( "Question 1097515: If 1/4 of a mixture rice and corn was replaced by corn alone, the resulting mixture becomes 55% corn. What was the percentage of corn in the original mixture? \n" ); document.write( "

Algebra.Com's Answer #711993 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "Let \"M\" be the the total amount/(mass) of the original mixture,\r\n" );
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document.write( "and let \"x\" be the fraction  of corn in the original mixture (the unknown under the question).\r\n" );
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document.write( "Then the amount of corn after replacing is  (0.75*xM + 0.25*M),\r\n" );
document.write( "and the equation for the given corn percentage is\r\n" );
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document.write( " = 0.55.\r\n" );
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document.write( "Cancel the factor M in the numerator and denominator. You will get\r\n" );
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document.write( "0.75x + 0.25 = 0.55  ====>  0.75x = 0.55 - 0.25 = 0.3  ====>  x =  =  = 0.4.\r\n" );
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document.write( "Answer.  The percentage of corn in the original mixture was 40%.\r\n" );
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