document.write( "Question 1097303: SHOW THAT IF B IS A SUBSET OF A, THEN P(B)<= P(A) \n" ); document.write( "
Algebra.Com's Answer #711952 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "U = universal set\r
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\n" ); document.write( "\n" ); document.write( "Let's say that the universal set U has p items inside it where p is some positive integer\r
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\n" ); document.write( "\n" ); document.write( "Define positive integers m and n such that \"m+%3C=+n+%3C=+p\"\r
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\n" ); document.write( "\n" ); document.write( "Set A has n items inside it\r
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\n" ); document.write( "\n" ); document.write( "while set B has m items inside it\r
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\n" ); document.write( "\n" ); document.write( "Every item inside set B is also found in set A. This makes set B a subset of set A.\r
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\n" ); document.write( "\n" ); document.write( "The probability of selecting an item from set A is \"n%2Fp\" since we have n items from set A and p items from set U.\r
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\n" ); document.write( "\n" ); document.write( "The probability of selecting an item from set B is \"m%2Fp\" since we have m items from set B and p items from set U.\r
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\n" ); document.write( "\n" ); document.write( "Because \"m+%3C=+n\", this means that \"m%2Fp+%3C=+n%2Fp\".
\n" ); document.write( "We can divide both sides of the first inequality (\"m+%3C=+n\") by p to get the second inquality (\"m%2Fp+%3C=+n%2Fp\").
\n" ); document.write( "The inequality sign will not flip because p is a positive number.\r
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\n" ); document.write( "\n" ); document.write( "So this proves that P(B) <= P(A) is true, since,
\n" ); document.write( "P(A) = n/p
\n" ); document.write( "P(B) = m/p\r
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