document.write( "Question 97846: A garden area is 30 ft long and 20 ft wide. A path of uniform width is set around the edge. If the remaining garden is 400 ft^2, what is the width of the path.\r
\n" ); document.write( "\n" ); document.write( "I tried (x is width of path):
\n" ); document.write( "(30-x)(20-x)=400
\n" ); document.write( "600-30x-20x+x^2=400
\n" ); document.write( "x^2-50x+600=400
\n" ); document.write( "x^2-50x+600-400=0
\n" ); document.write( "x^2-50x+200=0\r
\n" ); document.write( "\n" ); document.write( "I then tried the quadratic equation with a=1, b=-50, c=200 and ended up with x=25 +- 5 radical 17\r
\n" ); document.write( "\n" ); document.write( "Help!!!! Thanks!
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Algebra.Com's Answer #71194 by mathslover(157)\"\" \"About 
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you were close
\n" ); document.write( "the place where you erred was in taking the length as 30 -x
\n" ); document.write( "Since its a path running around you have to consider 2 sides.So the length
\n" ); document.write( "would be 30 -2x and the width 20 -2x
\n" ); document.write( "Now you can procced as earlier,\r
\n" ); document.write( "\n" ); document.write( "(30-2x)(20-2x)=400
\n" ); document.write( "600-100x + 4x^2 =400
\n" ); document.write( "4x^2 -100x +200=0
\n" ); document.write( "x^2 -25x + 50 =0
\n" ); document.write( "x= (25 +- 5sqrt(17))/2
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\n" ); document.write( "we take only
\n" ); document.write( "(25 - 5sqrt(17))/2 since the other root makes the widt greater than the side
\n" ); document.write( "=2.192 ft\r
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