document.write( "Question 97741: A coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of a coffee that sells for $8 per pound should be mixed with the 20 pouds of $4 per pound coffee to obtain a blend that will sell for $5? How much of the $5 per pound coffee is there to sell? \n" ); document.write( "

Algebra.Com's Answer #71191 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of a coffee that sells for $8 per pound should be mixed with the 20 pounds of $4 per pound coffee to obtain a blend that will sell for $5?
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\n" ); document.write( "Let x = amt of $8 coffee required
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\n" ); document.write( "It says it will be mixed with 20 lb of $4 coffee, therefore:
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\n" ); document.write( "Resulting amt = (x+20)
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\n" ); document.write( "Simple equation:
\n" ); document.write( "4(20) + 8x = 5(x+20)
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\n" ); document.write( "80 + 8x = 5x + 100
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\n" ); document.write( "8x - 5x = 100 - 80
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\n" ); document.write( "3x = 20
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\n" ); document.write( "x = 20/3
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\n" ); document.write( "x = 6 $\"2%2F3\"$ lb of $8 coffee required
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\n" ); document.write( "\"How much of the $5 per pound coffee is there to sell?\"
\n" ); document.write( "20 + 6 $\"2%2F3\"$ = 26 $\"2%2F3\"$ lb of $5 coffee to sell
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\n" ); document.write( "Check solution:
\n" ); document.write( "4(20) + 8(6 $\"2%2F3\"$ ) = 5(26 $\"2%2F3\"$ )
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\n" ); document.write( "Using a calculator
\n" ); document.write( "80 + 53.3333 = 133.3333, proves our solution
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\n" ); document.write( "Did this make sense to you? \n" ); document.write( "

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