document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97846>Question 97846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden area is 30 ft long and 20 ft wide.  A path of uniform width is set around the edge.  If the remaining garden is 400 ft^2, what is the width of the path.\r<BR>\n" );
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document.write( "I tried (x is width of path):<BR>\n" );
document.write( "(30-x)(20-x)=400<BR>\n" );
document.write( "600-30x-20x+x^2=400<BR>\n" );
document.write( "x^2-50x+600=400<BR>\n" );
document.write( "x^2-50x+600-400=0<BR>\n" );
document.write( "x^2-50x+200=0\r<BR>\n" );
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document.write( "I then tried the quadratic equation with a=1, b=-50, c=200 and ended up with x=25 +- 5 radical 17\r<BR>\n" );
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document.write( "Help!!!!  Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71190 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THIS IS WHY A STRONGLY RECOMMEND YOU DRAW A DIAGRAM BEFORE YOU START TO SOLVE THESE TYPE OF PROBLEMS. YOU SHOULD HAVE DRAWN A 20 BY 30 RECTANGLE.<BR>\n" );
document.write( "THIS GIVES YOU A 20*30=600 SQUARE FT.<BR>\n" );
document.write( "NOW DRAW A BORDER INSIDE THIS RECTANGLE WITH A STANDARD WIDTH & LABEL THE WIDTH OF THE PATH=X.<BR>\n" );
document.write( "NOW SHOULD SEE THAT THE INSIDE AREA THAT=400 SQUARE FT. HAS THE LENGTH OF (30-2X) & HAS A WIDTH OF (20-2X).<BR>\n" );
document.write( "NOW SET THE PRODUCT OF THE LENGTH TIMES THE WIDTH EQUAL TO 400.<BR>\n" );
document.write( "(30-2X)(20-2X)=400 NOW MULTIPLY THE SIDE DIMENTIONS<BR>\n" );
document.write( "600-40X-60X+4X^2=400<BR>\n" );
document.write( "4X^2-100X+600-400<BR>\n" );
document.write( "4X^2-100+200=0 NOW WXTRACT THE 4 FROM ALL TERMS<BR>\n" );
document.write( "4(X^2-25X+50)=0 NOW FACTOR THE EQUATION<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "X=(25+-SQRT[-25^2-4*1*50])/281<BR>\n" );
document.write( "X=(25+-SQRT[625-200])/2<BR>\n" );
document.write( "X=(25+-SQRT425)/2<BR>\n" );
document.write( "X=(25+-20.62)/2<BR>\n" );
document.write( "X=45.62/2<BR>\n" );
document.write( "X=22.81 FT. THIS CANNOT BE THE ANSWER BECAUSE IT IS WIDER THAN THE ENTIRE GARDEN.<BR>\n" );
document.write( "X=(25-20.62)/2<BR>\n" );
document.write( "X=4.38/2<BR>\n" );
document.write( "X=2.19 FT. ANSWER FOR THE WIDTH OF THE PATH.<BR>\n" );
document.write( "PLUG IN THESE FIGURES INTO YOUR DIAGRAM FOR THE PROOF.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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