document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097474>Question 1097474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tom is twice as old as Andy. In 4 years time the sum of the ages will be 32 years. Find Andy’s present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711897 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let T=Tom's Age, A=Andy's Age\r<BR>\n" );
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document.write( "Then T=2A and (T+4)+(T/2)+4=32\r<BR>\n" );
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document.write( "So that (3/2)T+8=32 --> (3/2)T=24 --> T=48/3=16\r<BR>\n" );
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document.write( "Therefore, A=16/2=8 (Answer) </SPAN>\n" );
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