document.write( "Question 1097414: The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car traveling 50 mph can stop in 110 ​ft, how many feet will it take the same car to stop when it is traveling 100 ​mph? It will take how many feet? Please give exact answer!! \n" ); document.write( "
Algebra.Com's Answer #711846 by KMST(5328)\"\" \"About 
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When a variable (like braking distance, d, in feet)
\n" ); document.write( "varies directly with some other variable (like the square of the speed, with r=speed measured in mph),
\n" ); document.write( "as one variable changes by a factor, so does the other.
\n" ); document.write( "As the speed doubles, from 50 mph to 110 mph,
\n" ); document.write( "the square of the speed quadruples.
\n" ); document.write( "It changes from \"50%5E2=2500\" to \"100%5E2=10000\" ,
\n" ); document.write( "but we do not need to calculate to know
\n" ); document.write( "that when one number doubles its square quadruples.
\n" ); document.write( "The square of the speed quadrupled,
\n" ); document.write( "and so does the breaking distance,
\n" ); document.write( "from \"110ft\" to \"4%2A%28110ft%29=highlight%28440ft%29\" .
\n" ); document.write( "Easy mental math.
\n" ); document.write( "
\n" ); document.write( "If you were asked to write it as a function,
\n" ); document.write( "you would define \"k\" as a positive constant,
\n" ); document.write( "say that
\n" ); document.write( "\"d=k%2Ar%5E2\" ,
\n" ); document.write( "and substituting \"110\" for the distance and \"50\" for the speed,
\n" ); document.write( "you would find \"k\" :
\n" ); document.write( "\"110=k%2A50%5E2\" --> \"110=k%2A2500\" --> \"110%2F2500=k\" --> \"k=0.044\" .
\n" ); document.write( "Then, the function,would be
\n" ); document.write( "\"d=0.044%2Ar%5E2\" .
\n" ); document.write( "Then, you could use that function,
\n" ); document.write( "substituting \"100\" for \"r\" ,
\n" ); document.write( "to calculate the answer as
\n" ); document.write( "\"d=0.044%2A100%5E2=0.044%2A10000=440\" .
\n" ); document.write( "That would require a lot more writing and calculating.
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