document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097423>Question 1097423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve this problem in your notebook using all four steps.\r<BR>\n" );
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document.write( "Harvey is 3 times as old as Jane. The sum of their ages is 48 years. Find the age of each. \r<BR>\n" );
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document.write( "Jane is <BR>\n" );
document.write( "? years old.<BR>\n" );
document.write( "Harvey is <BR>\n" );
document.write( "? years old.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711838 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let H be Harvey's age and J be Jane's age, then<BR>\n" );
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document.write( "1)  H = 3 * J<BR>\n" );
document.write( "2)  H + J = 48<BR>\n" );
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document.write( "use equation 1) and substitute for H in equation 2)<BR>\n" );
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document.write( "3 * J + J = 48<BR>\n" );
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document.write( "4J = 48<BR>\n" );
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document.write( "J = 12<BR>\n" );
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document.write( "H = 3 * 12 = 36<BR>\n" );
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document.write( "Jane is 12 years old<BR>\n" );
document.write( "Harvey is 36 years old<BR>\n" );
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