document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097352>Question 1097352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Frida and Diego are both painters. At the time they met, Frida had sold 11 paintings and Diego had sold 37. From that point on, Frida sells 7 paintings per year and Diego sells 5 paintings per year. When they have sold the same number of paintings, how many paintings will each have sold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711810 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f=11+7y<BR>\n" );
document.write( "d=37+5y<BR>\n" );
document.write( "11+7y=37+5y<BR>\n" );
document.write( "2y=26<BR>\n" );
document.write( "y=13<BR>\n" );
document.write( "f=11+13*7=11+91=102<BR>\n" );
document.write( "d=37+13*5=37+65=102<BR>\n" );
document.write( "After 13 years they will each have sold 102 paintings.\r<BR>\n" );
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