document.write( "Question 1097373: 2. An envelope contains 26 money bills in $500 and $1,000 denominations. The amount of $500 bills is 30% of the total amount of money in the envelope. How many bills of each denomination are in the envelope? \n" ); document.write( "

Algebra.Com's Answer #711789 by ikleyn(52800) $\"\"$ $\"About$

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document.write( "Let \"x\" be the number of $500 bills.\r\n" );
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document.write( "Then the number of the $1000 bills is (26-x).\r\n" );
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document.write( "The condition says\r\n" );
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document.write( "500x = 0.3*(500x + 1000*(26-x)).\r\n" );
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document.write( "Simplify and solve for x:\r\n" );
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document.write( "500x = 150x + 7800 - 300x,\r\n" );
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document.write( "500x - 150x + 300x = 7800,\r\n" );
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document.write( "650x = 7800  ====>  x =  = 12.\r\n" );
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document.write( "Answer.  12 $500 bills and (26-12) = 14 $1000 bills.\r\n" );
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