document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097392>Question 1097392</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of pure peanuts must be combined with a 20% peanut mix to produce 2 pounds of a 50% peanut mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711787 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let pure peanuts be x. Then, 20% peanuts will be 0.2x<BR>\n" );
document.write( "0.2x + 1(2-x) = 0.50(2)<BR>\n" );
document.write( "0.2x + 2-x = 1<BR>\n" );
document.write( "-0.8x = -1<BR>\n" );
document.write( "x = 1.25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );