document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097327>Question 1097327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> mike rents a car for a total of £445. The rental charges are £145 for the first day and £60 per day after that. For how many days did Mike rent the car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711781 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>Using formal algebra, let d be the total number of days; then (d-1) is the number of days after the first day.  Then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=145%2B60%28d-1%29+=+445 ALIGN=MIDDLE  ALT=\"145%2B60%28d-1%29+=+445\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "That should be an easy equation to solve.<br><BR>\n" );
document.write( "You should also practice trying to solve the problem by logical analysis, perhaps to see if the answer you get using algebra is correct.<br><BR>\n" );
document.write( "The first day costs £145.  If the total cost was £445, how much is left after that first day?<BR>\n" );
document.write( "Then if each additional day costs £60, how many additional days can he rent the car for with the amount that is left?<BR>\n" );
document.write( "And so how many days total is that? </SPAN>\n" );
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