document.write( "Question 1097306: Simplify: sinβ secβ + cosβ cscβ \n" ); document.write( "
Algebra.Com's Answer #711774 by Boreal(15235)\"\" \"About 
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sec beta=1/cos beta; csc beta=1/sin beta
\n" ); document.write( "therefore sin beta*sec beta=sin beta/cos beta=tan beta.
\n" ); document.write( "cos beta*csc beta,
\n" ); document.write( "cos beta*csc beta= cos beta/ sin beta=ctn beta\r
\n" ); document.write( "\n" ); document.write( "The sum is sin beta/cos beta+ cos beta/sin beta.
\n" ); document.write( "common denominator of sin beta* cos beta
\n" ); document.write( "Numerator becomes sin^2 beta+cos^2 beta=1\r
\n" ); document.write( "\n" ); document.write( "Therefore, the sum is 1/sin beta*cos beta ANSWER
\n" ); document.write( "Check
\n" ); document.write( "Let beta=30 degrees
\n" ); document.write( "sin beta*sec beta=0.5774, same as tan 30
\n" ); document.write( "cos beta*csc beta=1.732, same as ctn 30. Their sum is 2.31
\n" ); document.write( "(1/2)*2/sqrt(3) is first term=1/sqrt (3)
\n" ); document.write( "sqrt(3)/2*2= sqrt(3) is the second term. The sum is sqrt(3)+1/sqrt(3)=2.31\r
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