document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097348>Question 1097348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tea bag is shaped like a regular square pyramid. Each leg of the base is 4 cm, and the slant height is 5 cm. Find the VOLUME of the tea bag. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711747 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A tea bag is shaped like a regular square pyramid. Each leg of the base is 4 cm, and the slant height is 5 cm. Find the VOLUME of the tea bag. <BR>\n" );
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document.write( "Sketch the figure::<BR>\n" );
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document.write( "Find the diagonal of the base:: d^2 = 4^2+4^2; d = 4*sqrt(2)<BR>\n" );
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document.write( "Find the height::<BR>\n" );
document.write( "h^2 = 5^2 + (2sqrt(2))^2<BR>\n" );
document.write( "h^2 = 5^2 + 8 = 33<BR>\n" );
document.write( "height = sqrt(33)<BR>\n" );
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document.write( "Ans:: Volume = (1/3)(height)(area of base) = (1/3)(sqrt(33))16 cm^2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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