document.write( "Question 1097304: Two dice are rolled. Find the probability of getting the following.
\n" ); document.write( "2) a sum of 6 or 7 or 8 b) doubles or a sum of 4 or 6 c) a sum greater than 9 or less than 4,\r
\n" ); document.write( "\n" ); document.write( "Please help me answer this. \n" ); document.write( "
Algebra.Com's Answer #711712 by Boreal(15235)\"\" \"About 
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Probability of a 6 is 5/36; a 7 is 6/36, and 8 is 5/36 (symmetric)
\n" ); document.write( "That is 16/36 or 4/9.
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\n" ); document.write( "doubles is 6*(1/36)=1/6
\n" ); document.write( "sum of 4 or 6 is 3/36+5/36=8/36
\n" ); document.write( "Two of those 8 are doubles and have already been counted, so the sum is 14/36-2/36=12/36 or 1/3.
\n" ); document.write( "Of the 36 outcomes, (1,1), (2,2), (3,3), (4,4), (5,5), (6,6), (3,1), (1,3), (1, 5), (2, 4), (4, 2), (5, 1)
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\n" ); document.write( "Sum greater than 9 is 10, 11, 12 or 3/36+2/36+1/36, or 6/36
\n" ); document.write( "Less than 4 is 3 or 2 which is 2/36+1/36 or 3/36.
\n" ); document.write( "The answer is their sum or 9/36 or 1/4.
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\n" ); document.write( "2/12 have 1/36 probability
\n" ); document.write( "3/11 have 2/36
\n" ); document.write( "4/10 have 3/36
\n" ); document.write( "5/9 have 4/36
\n" ); document.write( "6/8 have 5/36
\n" ); document.write( "7 has 6/36 \n" ); document.write( "
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