document.write( "Question 14207: x=4y-10
\n" ); document.write( "5x+3y=-4 \n" ); document.write( "
Algebra.Com's Answer #7117 by elima(1433)\"\" \"About 
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x=4y-10
\n" ); document.write( "5x+3y=-4\r
\n" ); document.write( "\n" ); document.write( "You want to use substitution to solve this.
\n" ); document.write( "We already have an answer for x (only the begin, not our final answer).
\n" ); document.write( "This is only to start the problem,
\n" ); document.write( "5(4y-10)+3y=-4
\n" ); document.write( "Distribute the 5;
\n" ); document.write( "20y-50+3y=-4
\n" ); document.write( "Add like terms;
\n" ); document.write( "20y+3y-50=-4
\n" ); document.write( "23y-50=-4
\n" ); document.write( "Add 50 to both sides;
\n" ); document.write( "23y-50+50=-4+50
\n" ); document.write( "23y=46
\n" ); document.write( "Divide both sides by 23;
\n" ); document.write( "\"23y%2F23=46%2F23\"
\n" ); document.write( "y=2
\n" ); document.write( "Now we have what y =, so now we go back to either equation and plug in 2 for y, and figure out x.
\n" ); document.write( "5x+3(2)=-4
\n" ); document.write( "5x+6=-4
\n" ); document.write( "Subtract 6 from both sides;
\n" ); document.write( "5x+6-6=-4-6
\n" ); document.write( "5x=-10
\n" ); document.write( "Divide both sides by 5;
\n" ); document.write( "\"5x%2F5=-10%2F5\"
\n" ); document.write( "x=-2
\n" ); document.write( "So we end with;
\n" ); document.write( "x=-2
\n" ); document.write( "y=2
\n" ); document.write( "Hope you understand
\n" ); document.write( "=) \n" ); document.write( "
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