document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097210>Question 1097210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know the sq. ft of surface area in a 2\" x 4\" oval pipe. The pipe is 6'4\" long.\r<BR>\n" );
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document.write( "This a running board on a truck that I am painting. I have two of them..\r<BR>\n" );
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document.write( "Again, I need to know the total surface area\r<BR>\n" );
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document.write( "Thank You\r<BR>\n" );
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document.write( "William Brown\r<BR>\n" );
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document.write( "My email is:\r<BR>\n" );
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document.write( "1RAM5689@gmail.com </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711684 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the pipe can be approximated by an ellipse, then you can use Area = perimeter*length.  Since the major radius is less than 3 times the minor radius, the perimeter, P, of the pipe USING the ELLIPSE APPROXIMATION is:<BR>\n" );
document.write( "    P  = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++2%2Api%2Asqrt%28%28%28a%5E2+%2B+b%5E2%29%29%2F2%29+ ALIGN=MIDDLE  ALT=\"++2%2Api%2Asqrt%28%28%28a%5E2+%2B+b%5E2%29%29%2F2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "where a and b are the major axis and minor axis lengths, respectively (similar to radius of a circle, except for a circle a=b=r).  \r<BR>\n" );
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document.write( "We have <BR>\n" );
document.write( "a=4/2 = 2 in.<BR>\n" );
document.write( "b = 2/2 = 1 in.\r<BR>\n" );
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document.write( "P  = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++2%2Api%2Asqrt%28%282%5E2+%2B+1%5E2%29%2F2%29+ ALIGN=MIDDLE  ALT=\"++2%2Api%2Asqrt%28%282%5E2+%2B+1%5E2%29%2F2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  or approx. 9.9346 in.<BR>\n" );
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document.write( "Length of running board is  6*12 + 4 = 76 in.<BR>\n" );
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document.write( "Surface area = P * length = 9.9346 in. * 76 in = 755.03 sq in.\r<BR>\n" );
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document.write( "Since you have two of them, that brings the total area to 2*755.03 =  <b>1510.06 sq in.</b>  or, converting to sq ft:  1510.06/144 = <b>10.49 sq ft.</b>\r<BR>\n" );
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