document.write( "Question 97730: A sphere has an area \"64pi\", what is its volume? \n" ); document.write( "
Algebra.Com's Answer #71166 by Edwin McCravy(20056)\"\" \"About 
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A sphere has an area \"64pi\", what is its volume?
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document.write( "You need the formulas\r\n" );
document.write( "\"A+=+4pi%2Ar%5E2\" and \"V=%284%2F3%29pi%2Ar%5E3\"\r\n" );
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document.write( "We are given \"A=64pi\", so we substitute in\r\n" );
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document.write( "\"A+=+4pi%2Ar%5E2\"\r\n" );
document.write( "\"64pi+=+4pi%2Ar%5E2\"\r\n" );
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document.write( "Divide both sides by \"4pi\"\r\n" );
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document.write( "\"%2864pi%29%2F%284pi%29+=+%284pi%2Ar%5E2%29%2F%284pi%29\"\r\n" );
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document.write( "\"16+=+r%5E2\"\r\n" );
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document.write( "Take positive square roots of both sides:\r\n" );
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document.write( "\"sqrt%2816%29=sqrt%28r%5E2%29\"\r\n" );
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document.write( "\"4+=+r\"\r\n" );
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document.write( "Substitute 4 for r in\r\n" );
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document.write( "\"V=%284%2F3%29pi%2Ar%5E3\"\r\n" );
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document.write( "\"V=%284%2F3%29pi%2A4%5E3\"\r\n" );
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document.write( "\"V=%284%2F3%29pi%2A64\"\r\n" );
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document.write( "\"V=%28256%2F3%29pi\" \r\n" );
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document.write( "\"V=264.9409805\"\r\n" );
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document.write( "Edwin
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