document.write( "Question 1097251: solve this.
\n" ); document.write( "3 7 14 27 52 ......
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Algebra.Com's Answer #711648 by greenestamps(13200)\"\" \"About 
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There is no way to \"solve\" this, or any other problem like this.

\n" ); document.write( "You could put any number next and it would be a valid sequence.

\n" ); document.write( "The only way to get the \"right\" answer is to ask the author of the problem what answer he had in mind.

\n" ); document.write( "It is always possible to find AN answer to a problem like this. Any sequence of n terms can be fitted by a polynomial of degree (n-1). So with your sequence of 5 numbers, there is a polynomial of the form \"p%28n%29+=+an%5E4%2Bbn%5E3%2Bcn%5E2%2Bdn%2Be\" that will produce the given sequence.

\n" ); document.write( "To find that polynomial, you simply form a system of 5 equations in the 5 unknowns a, b, c, d, and e. The 5 equations are
\n" ); document.write( "\"a%2Bb%2Bc%2Bd%2Be=3\" <-- p(1)
\n" ); document.write( "\"16a%2B8b%2B4c%2B2d%2Be+=+7\" <-- p(2)
\n" ); document.write( "...
\n" ); document.write( "\"625a%2B125b%2B25c%2B5d%2Be+=+52\" <-- p(5)

\n" ); document.write( "The calculations are straightforward, but very tedious.

\n" ); document.write( "Or a graphing calculator with matrix capability can be used to make the work relatively easy.

\n" ); document.write( "But the answer obtained using the degree 4 polynomial might not be the \"right\" one that the author of the problem wanted........


\n" ); document.write( "I see that another tutor has already supplied an answer that is very similar to one I was going to add to my response....

\n" ); document.write( "If you notice that the numbers are \"approximately doubled\" each time, you can figure out a pattern:
\n" ); document.write( "3*2 plus 1 gives you 7
\n" ); document.write( "7*2 plus 0 gives you 14
\n" ); document.write( "14*2 plus -1 gives you 27
\n" ); document.write( "27*2 plus -2 gives you 52

\n" ); document.write( "To get an explicit formula for the n-th term in the sequence, note that the first term is 3 and each term after that is approximately 2 times the previous term. Then the explicit formula is going to be something of the form
\n" ); document.write( "\"3%2A2%5E%28n-1%29\"

\n" ); document.write( "The values produced by that formula alone are
\n" ); document.write( " 3, 6, 12, 24, 48, ...

\n" ); document.write( "Comparing those values to the actual values
\n" ); document.write( " 3, 7, 14, 27, 52, ...
\n" ); document.write( "we see that an explicit formula for the n-th term in the sequence is
\n" ); document.write( "\"3%2A2%5E%28n-1%29%2B%28n-1%29\"


\n" ); document.write( "Finally, note that the sequence you get from the polynomial method I described first will be different from the one produced by this other method.

\n" ); document.write( "And while both sequences would be valid answers to the problem, it is far more likely that the intended answer is the one obtained by this second method.
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