document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097212>Question 1097212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the quadratic function in standard form and find the vertex.\r<BR>\n" );
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document.write( "f(x)=1/2x^2+10x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711647 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Move the 4 to the right so (1/2)x^2+10x=-4<BR>\n" );
document.write( "Factor out a (1/2) <BR>\n" );
document.write( "(1/2)(x^2+20x)=-4<BR>\n" );
document.write( "complete the square<BR>\n" );
document.write( "(1/2)(x+10)^2=-4+50; the 10^2=100 is multiplied by (1/2)<BR>\n" );
document.write( "(1/2)(x+10)^2-46=0<BR>\n" );
document.write( "vertex is (-10, -46)<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "vertex x is -b/2a=-10/1=-10<BR>\n" );
document.write( "f(-10)=-46<BR>\n" );
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