document.write( "Question 1097197: Solve the following equations:\r
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document.write( "1.) X= (2/x+1)
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document.write( "2.) x+3 =(28/x)
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document.write( "3.) (3/x+1)=sq. root of (x+2) \n" );
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Algebra.Com's Answer #711606 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=(2/(x+1)) \n" ); document.write( "x(x+1)=2 \n" ); document.write( "x^2+x-2=0 \n" ); document.write( "(x+2)(x-1)=0 \n" ); document.write( "x=-2, 1 \n" ); document.write( "check in original \n" ); document.write( "-2=2/(-1), checks \n" ); document.write( "1=2/2, checks. \n" ); document.write( "================ \n" ); document.write( "x+3=(28/x) \n" ); document.write( "x^2+3x=28 \n" ); document.write( "x^2+3x-28=0 \n" ); document.write( "(x+7)(x-4)=0 \n" ); document.write( "x=4, -7 \n" ); document.write( "checks \n" ); document.write( "=============== \n" ); document.write( "3/(x+1)=sqrt(x+2) \n" ); document.write( "9/(x^2+2x+1)=x+2 \n" ); document.write( "9=x^3+2x^2+2x^2+4x+x+2 \n" ); document.write( "0=x^3+4x^2+5x-7 \n" ); document.write( "numerically, this is x=0.79, which when substituted has 1.675=1.67, same given rounding. \n" ); document.write( " |