document.write( "Question 1097183: Find a linear function h given h(-3)=3 and h(0)=2. Then find h(-6). Show all work. \n" ); document.write( "
Algebra.Com's Answer #711595 by Fombitz(32388)\"\" \"About 
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\"h%28x%29=ax%2Bb\"
\n" ); document.write( "So then,
\n" ); document.write( "\"h%28-3%29=a%28-3%29%2Bb=3\"
\n" ); document.write( "1.\"-3a%2Bb=3\"
\n" ); document.write( "and
\n" ); document.write( "\"h%280%29=a%280%29%2Bb=2\"
\n" ); document.write( "2.\"b=2\"
\n" ); document.write( "Substituting into eq. 1,
\n" ); document.write( "\"-3a%2B2=3\"
\n" ); document.write( "\"-3a=1\"
\n" ); document.write( "\"a=-1%2F3\"
\n" ); document.write( "So,
\n" ); document.write( "\"h%28x%29=-x%2F3%2B2\"
\n" ); document.write( "When \"x=-6\",
\n" ); document.write( "\"h%28-6%29=-%28-6%29%2F3%2B2=2%2B2=4\"
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