document.write( "Question 1097143: good morning, this is my questiion. Dave can hike on level ground 3 miles an hour faster that he can on uphill terrain.Yesterday, he hiked 27 miles spending 2 hours on level ground and 5 hours on uphill terrain. find his average speed on level ground. \r
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Algebra.Com's Answer #711593 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Average speed is ALWAYS:
\n" ); document.write( "[ distance traveled ] / [ time spent traveling ]
\n" ); document.write( "Let \"+s+\" = his speed on uphill terrain
\n" ); document.write( "\"+s+%2B+3+\" = his speed on level ground
\n" ); document.write( "----------------------------------------
\n" ); document.write( "\"+s%2A5+%2B+%28+s+%2B+3+%29%2A2+=+27+\"
\n" ); document.write( "\"+5s+%2B+2s+%2B+6+=+27+\"
\n" ); document.write( "\"+7s+=+21+\"
\n" ); document.write( "\"+s+=+3+\" mi/hr
\n" ); document.write( "and
\n" ); document.write( "\"+s+%2B+3+=+6+\" mi/hr
\n" ); document.write( "--------------------------
\n" ); document.write( "His average speed on level ground was 6 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "\"+s%2A5+%2B+%28+s%2B3+%29%2A2+=+27+\"
\n" ); document.write( "\"+3%2A5+%2B+6%2A2+=+27+\"
\n" ); document.write( "\"+15+%2B+12+=+27+\"
\n" ); document.write( "\"+27+=+27+\"
\n" ); document.write( "OK
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