document.write( "Question 97784: Find the vertices and foci of the ellipse given by:\r
\n" ); document.write( "\n" ); document.write( " x^2+9y^2-24x+18y+9=0
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Algebra.Com's Answer #71159 by mathslover(157)\"\" \"About 
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The standard form of the equation of an ellipse is \r
\n" ); document.write( "\n" ); document.write( "\"+%28x-h%29%5E2%2Fa%5E2++%2B+%28y-k%29%5E2%2Fb%5E2+=1+\" where (h,k) is the center of the ellipse\r
\n" ); document.write( "\n" ); document.write( "we first try and put the given equation in the standard form \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B9y%5E2-24x%2B18y%2B9=0\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2+-24x+%2B+144++%2B+9y%5E2+%2B+18y+%2B+9+-144+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2+-24x+%2B+144++%2B+9%28y%5E2+%2B+2y+%2B+1%29+=144\"
\n" ); document.write( "\"%28x-12%29%5E2+%2B+9%28y+%2B+1%29%5E2+=144+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x-12%29%5E2%29%2F144+%2B+%289%28y+%2B+1%29%5E2%29%2F144+=1+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x-12%29%5E2%29%2F144+%2B+%28y+%2B+1%29%5E2%2F16+=1+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x-12%29%5E2%29%2F12%5E2+%2B+%28y+-+%28-1%29%29%5E2%2F4%5E2+=1+\"\r
\n" ); document.write( "\n" ); document.write( "so we have the center (h,k) as (12,-1)\r
\n" ); document.write( "\n" ); document.write( "also a=12 and b=4
\n" ); document.write( "Since a > b the major axis is horizontal\r
\n" ); document.write( "\n" ); document.write( "vertices are given by (h-a,k) and (h+a,k)
\n" ); document.write( "so we have ( 12-12,-1) and (12+12,-1)
\n" ); document.write( "vertices are (0,-1) and (24,-1)\r
\n" ); document.write( "\n" ); document.write( "focii are at points given by (h-c,k) and (h+c,k) where c = \"sqrt%28a%5E2+-b%5E2%29\"
\n" ); document.write( "(12- 8*sqrt2,-1) and (12+ 8*sqrt2,-1)\r
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