document.write( "Question 1097170: A movie theater has two ticket prices: $8 for adults and $5 for children. I f the box office took in $4116 from the sale of 600 tickets how many tickerts of each kind were sold? \n" ); document.write( "
Algebra.Com's Answer #711580 by ikleyn(52802)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( " a + c = 600, (1) (counting tickets)\r\n" ); document.write( "8a + 5c = 4116. (2) (counting dollars)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "To solve, express c = 600-a from (1) and substitute it into (2). You will get the single equation for a:\r\n" ); document.write( "\r\n" ); document.write( "8a + 5*(600-a) = 4116.\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve it. Then evaluate c = 600-a.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is very standard problem on tickets (actually, on solving systems of linear equations in 2 unknowns).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "See the lesson\r \n" ); document.write( "\n" ); document.write( " - Using systems of equations to solve problems on tickets \r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |