document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097155>Question 1097155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the external angle of a triangle are in ratio 4:5:6, find the ratio of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711557 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the exterior angles = 360<BR>\n" );
document.write( "Let A = the smallest exterior angle<BR>\n" );
document.write( "Then the other two angles are 5/4A and 6/4A<BR>\n" );
document.write( "Find A:<BR>\n" );
document.write( "A + 5/4A + 6/4A = 360<BR>\n" );
document.write( "15/4A = 360<BR>\n" );
document.write( "A = 96<BR>\n" );
document.write( "The interior angles are, therefore, 180 - 96, 180 - (5/4)96, and 180 - (6/4)96<BR>\n" );
document.write( "Interior angles: a = 84, b = 60, c = 36<BR>\n" );
document.write( "So the ratio of the triangle is 60/84 = 5/7, 60/36 = 5/3, or 3:5:7 </SPAN>\n" );
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