document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097096>Question 1097096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Grade 9 question:\r<BR>\n" );
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document.write( "A man lent Rs. 1800 to Rohit at a certain rate of interest and Rs. 2300 to Mohit at 1% higher interest rate. If his annual income from both these sources be Rs. 248.50, find interest rate charged from both respectively.\r<BR>\n" );
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document.write( "Answer to the question is 5.5% and 6.5%.\r<BR>\n" );
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document.write( "I am unable to find steps for the solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711490 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13216)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>Let x be the interest rate on the first loan; then x+.01 is the interest rate on the second.<br><BR>\n" );
document.write( "The interest on the first loan is 1800x; the interest on the second is 2300(x+.01).<br><BR>\n" );
document.write( "Since the total interest is 248.50,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1800%28x%29+%2B+2300%28x%2B.01%29+=+248.50 ALIGN=MIDDLE  ALT=\"1800%28x%29+%2B+2300%28x%2B.01%29+=+248.50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "It should be straightforward to solve from there.... </SPAN>\n" );
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