document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097061>Question 1097061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2/3y + 1/4x = 2<BR>\n" );
document.write( "8y + 3x = a<BR>\n" );
document.write( "in this system of equations a is a constant.If the system has infinite solutions, what is the value of a? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711460 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>For a system of two linear equation to have an infinite number of solutions, the two equations must represent the same line.  Algebraically, that means each equation is a multiple of the other.<br><BR>\n" );
document.write( "In the given pair of equations, the coefficient of y in the second equation is 12 times the coefficient of y in the first equation (2/3 times 12 equals 8), and the coefficient of x in the second equation is 12 times the coefficient of x in the first equation (1/4 times 12 equals 3).  So the constant in the second equation has to be 12 times the constant in the first equation: 2*12 = 24.<br><BR>\n" );
document.write( "Answer: a = 24 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );