document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1097000>Question 1097000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From 4 men and 2 women. 3 persons are chossen at random to form a committee. find the probability that the committee consists of at least one person on either sex<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711402 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 4 men and 2 women. 3 persons are chosen at random to form a committee. find the probability that the committee consists of at least one person on either sex.<BR>\n" );
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document.write( "# of ways to have:<BR>\n" );
document.write( "1 woman and 2 men:: 2*4C2 = 2*6 = 12<BR>\n" );
document.write( "2 woman and 1 man:: 1*4 = 4<BR>\n" );
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document.write( "# of random sets of 3: 6C3 = (6*5*4)/(1*2*3) = 20<BR>\n" );
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document.write( "Answer::(12+4)/20 = 16/20 = 4/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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